ImageVerifierCode 换一换
格式:DOC , 页数:16 ,大小:1.62MB ,
资源ID:874228      下载积分:5 文钱
快捷下载
登录下载
邮箱/手机:
温馨提示:
快捷下载时,用户名和密码都是您填写的邮箱或者手机号,方便查询和重复下载(系统自动生成)。 如填写123,账号就是123,密码也是123。
特别说明:
请自助下载,系统不会自动发送文件的哦; 如果您已付费,想二次下载,请登录后访问:我的下载记录
支付方式: 支付宝    微信支付   
验证码:   换一换

加入VIP,省得不是一点点
 

温馨提示:由于个人手机设置不同,如果发现不能下载,请复制以下地址【https://www.wenke99.com/d-874228.html】到电脑端继续下载(重复下载不扣费)。

已注册用户请登录:
账号:
密码:
验证码:   换一换
  忘记密码?
三方登录: QQ登录   微博登录 

下载须知

1: 本站所有资源如无特殊说明,都需要本地电脑安装OFFICE2007和PDF阅读器。
2: 试题试卷类文档,如果标题没有明确说明有答案则都视为没有答案,请知晓。
3: 文件的所有权益归上传用户所有。
4. 未经权益所有人同意不得将文件中的内容挪作商业或盈利用途。
5. 本站仅提供交流平台,并不能对任何下载内容负责。
6. 下载文件中如有侵权或不适当内容,请与我们联系,我们立即纠正。
7. 本站不保证下载资源的准确性、安全性和完整性, 同时也不承担用户因使用这些下载资源对自己和他人造成任何形式的伤害或损失。

版权提示 | 免责声明

本文(半导体物理与器件第四版课后习题答案.doc)为本站会员(h****)主动上传,文客久久仅提供信息存储空间,仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。 若此文所含内容侵犯了您的版权或隐私,请立即通知文客久久(发送邮件至hr@wenke99.com或直接QQ联系客服),我们立即给予删除!

半导体物理与器件第四版课后习题答案.doc

1、Semiconductor Physics and Devices: Basic Principles, 4th edition Chapter 4By D. A. Neamen Problem Solutions_1Chapter 44.1kTENngciexp2gOc30where and are the values at 300 K.c(a) Silicon(K)T(eV)kT(cm )in320460172.3458. 41068.27.9(b) Germanium (c) GaAs(K)T(cm )in3(cm )in32046106.248. 8.91027.5_4.2Plot_

2、4.3(a) kTENngciexp2319191 04.08.05T25.exp33823019.105. T259.expBy trial and error, K367T(b)252120.05inTT9.301exp39.8By trial and error, K.47_4.4At K, 20T30259.keV176.At K, 44.eV035.1721024.70in01726.exp345.3023ggE345.8gg985exp1025.37gEor 174.3802.3ln96.817gEor eV1Now3210047. ocN5.18exp7216237.09.5oc

3、so cm4.ocN_Semiconductor Physics and Devices: Basic Principles, 4th edition Chapter 4By D. A. Neamen Problem Solutions_24.5kTkTAnBi 20.exp90.exp1.For K, eV2T176.For K, eV325For K, eV40034(a) For K,61025.9176.expAnBi(b) For K,30T43.25.i(c) For K,4310.0.expAnBi_4.6(a) kTEEfgFcFcexpcckTFcexpLet xEcThen

4、 kfgFTo find the maximum value:Txxdfcep21/0/1kkwhich yields2212/xTxThe maximum value occurs atkEc(b)kTEEfgFFexp1kTFexpLet xEThen fgF1To find the maximum value0expkTdxfdSame as part (a). Maximum occurs at2kTorE_4.7kTEEncccc221121expwhereand kTc4122cThenkEkEn121exp5.3exp24or085.21En_4.8Plot_Semiconduc

5、tor Physics and Devices: Basic Principles, 4th edition Chapter 4By D. A. Neamen Problem Solutions_34.9Plot_4.10*ln43pmidgapFi kTESilicon: , o56.0* om08.1eV2idgapFiGermanium: , o37.*on5.*eVmidgapiEGallium Arsenide: , op48.0*onm67.*eV32.midgapFi_4.11cmidgapFi NkTEln21kT4952.08.04l19(K)T(eV)k( )(eV)mid

6、gapFiE204672.345018. 086.1725._4.12(a) *ln43pmidgapFi kTE21.70l59.0meV631(b) 08.5ln.4midgapFiEmeV7._4.13Let constantKEgcThendfnFEcoEkTKcFexp1dcELet so that kTkTWe can writecFcFEEso thatexpexpexpkTkTFThe integral can then be written asdEKnFco 0which becomeskTkFcoexp_4.14Let for ccECg1cThendfnFEcoEkTC

7、cFcexp1dECc 1Let so that kTkTdWe can writeFcFEESemiconductor Physics and Devices: Basic Principles, 4th edition Chapter 4By D. A. Neamen Problem Solutions_4ThenkTECnFcoexp1dEkcEcc eorkTCnFoexp1dk0We find that1expexp00 dSokTEkCnFco21_4.15We have *1marooFor germanium, , 6r o5.0Then3.295.0161ororA4.1Th

8、e ionization energy can be written aseV6.132*somEeV09.65.02E_4.16We have *1marooFor gallium arsenide, , 1.3rom067*ThenoAr45.067.131The ionization energy is6.13.076.1322*somEoreV05._4.17(a) ocFcnNkTEl159078.2l059.eV14(b) FcgFEEeV8.2.(c) kTNpoex0259.1p104.9cm36(d) Holes(e) ioFinkTEl105.7l0259.eV38_4.1

9、8(a) oFpNkTEln169024.l059.eV16(b) EEFgFceV8.(c) 0259.exp8.219oncm34Semiconductor Physics and Devices: Basic Principles, 4th edition Chapter 4By D. A. Neamen Problem Solutions_5(d) ioFi npkTEl1065.2l09.eV36_4.19(a) ocFcnNkTEl519028.l059.eV8436FcgFEE.1eV270(b) 0259.637exp4.9opcm1(c) p-type_4.20(a) eV0

10、3275.0259.kT.8exp17.4/oncm40532.041FcgFEEeV1.375.exp3072/8opcm9.4(b) 140.ln25FcEeV1.025.FcgeV46.09.exp718opcm2.3_4.21(a) eV03275.0259.kT.8exp18./oncm50632.01FcgFEEeV84.375.84exp30712/9opcm.7(b) ocFcnNkTEl1590862.l059.eV213eV47.EF0259.exp04.9opcm317_4.22(a) p-type(b) eV28.041.gFEkTNpFoex0259.p10.9cm4

11、23EEFgFceV8.1kTNnccoexp0259.48.219cm5303_Semiconductor Physics and Devices: Basic Principles, 4th edition Chapter 4By D. A. Neamen Problem Solutions_64.23(a) kTEnFiioexp0259.15.0cm37kTEnpFiioex0259.p15.0cm6733(b) kTEnFiioex0259.p18.6cm93kTEnpFiioex0259.p18.6cm233_4.24(a) oFpNkTEln15904.l0259.eV17(b)

12、 EEFgFceV2.8.(c) 059.1exp8.219oncm36(d) Holes(e) ioFi nkTEl105.l0259.eV34_4.25eV0345.0259.kT2/14.Ncm1906.32/198.2ccm193.43192 060.in45.2exp2467.5cm1038in3(a) oFpNkTEln15906.l0345.eV278(b) eV8427.273.FcE(c) 05.exp139.4oncm3(d) Holes(e) ioFi nkTEl125038.l045.eV26_4.26(a) 0259.exp178opcm45.3eV17.FcE025

13、9.exp17.oncm233Semiconductor Physics and Devices: Basic Principles, 4th edition Chapter 4By D. A. Neamen Problem Solutions_7(b) eV0345.kT2/3187Ncm9.32/1704ccm26.3oFpNkTEln14905.78l034.eV82eV2.1FcE0345.7exp36.77oncm402_4.27(a) 0259.exp104.9opcm683eV87.FcE0259.exp1.29oncm4373(b) eV05.kT2/190Ncm6.32/19

14、482ccm03.3oFpNkTEln149068.l0345.eV82eV7.1FcE0345.71exp13.49oncm08_4.28(a) FcoNn2/1For , kTEF5.0cThen .12/1F89oncm106.33(b) FcoN2/.17.4cm0353_4.29FoNp2/1F2/191904.05So 62/FWe find kTE.3eV07.2590FE_4.30(a) 4kTcFThen 0.62/1FcoNn2/1.8.9cm203Semiconductor Physics and Devices: Basic Principles, 4th editio

15、n Chapter 4By D. A. Neamen Problem Solutions_8(b) 0.617.42oncm833_4.31For the electron concentrationEfgnFcThe Boltzmann approximation applies, socnhm32/*4kTEFexporhEnFcn243/*kTEkTccexpDefineExcThenxKnepTo find maximum , setndx210/xxep12/orKxep02/1which yieldskTEkTcc212For the hole concentrationfgEpF

16、1Using the Boltzmann approximationEhmp32/*4kTFexorkTEhmEpFpex243/*kTpDefinekExThenxKpepTo find maximum value of , setxpEUsing the results from above, 0xdwe find the maximum atkTE21_4.32(a) Silicon: We havekTENnFccoexpWe can writeFdcFcEFor eV and eV045.d kTE3we can write29.exp18.29on7340orcm1745.2onW

17、e also havekTENpFoexAgain, we can writeEaFFForand eVka3045.EThen29.exp104.9op734orcm1602.9opSemiconductor Physics and Devices: Basic Principles, 4th edition Chapter 4By D. A. Neamen Problem Solutions_9(b) GaAs: assume eV058.dcEThen329.exp107.4on4orcm16087.on3Assume eV5.EaThen3029.4exp18op7orcm1620.9

18、op3_4.33Plot_4.34(a) cm1515034op3cm41520.7.n(b) cm6doN3cm1620.3.p3(c) cm105ion(d) 39192 754.8. i02.expcm134.7in3cm5aoNpcm81520.0.3(e) 1992 45.8. in02.3expcm17.in21321414 07.02oncm149.3cm1228.0.7op3_4.35(a) 154daoNpcm15033cm3262 08.8. oin(b) cm1d3cm4162.03.op3(c) cm68in(d) 31172 075.4i29.4expcm815.7i

19、n3cm04aoNpcm2152804. 3(e) 1872.0.4in45029.3expcm10853.incm4doNcm71420.p3_4.36(a) Ge: cm1304.2in(i) 2iddonN2131515 04.02Semiconductor Physics and Devices: Basic Principles, 4th edition Chapter 4By D. A. Neamen Problem Solutions_10orcm1502doNn31524.oipcm8.3(ii) 15607daocm1503315224.oipncm9.3(b) GaAs:

20、cm608i(i) cm152doNncm3156. p(ii) cm150daocm315268.38. n(c) The result implies that there is only one minority carrier in a volume of cm .30_4.37(a) For the donor levelkTENnFddexp21059.or 418.dNn(b) We havekTEEfFFexp1Now FcFor245.0kEThen0259.41expEfFor87.2fF_4.38(a) p-typedaN(b) Silicon:131305.2oporcm130.Thencm7132025.5oipn3Germanium:22idadao nNN2131313 04.05.05. orcm1326.opThencm13132076.4.0oinGallium Arsenide:cm5.daNp3andcm216.0.18362oin3_4.39(a) n-typeadN(b) 151502.oncm14083cm514028.oip3

Copyright © 2018-2021 Wenke99.com All rights reserved

工信部备案号浙ICP备20026746号-2  

公安局备案号:浙公网安备33038302330469号

本站为C2C交文档易平台,即用户上传的文档直接卖给下载用户,本站只是网络服务中间平台,所有原创文档下载所得归上传人所有,若您发现上传作品侵犯了您的权利,请立刻联系网站客服并提供证据,平台将在3个工作日内予以改正。