有机波谱分析纳米材料工程研究中心李春丽21. 所用仪器的频率是多少？2. 表达出该峰习题 11. 1539.18 / 3.847 = 400 MHz2. 3.82 (quint, J = 6.2 Hz, 1H)2. 3.82 (sept, J = 6.2 Hz, 1H)2. 3.82 (tt, J = 6.2 Hz, 1H)3This is a 90 MHz instrument. Report all 4 signals. Include multiplicity and coupling constants. 1 12 23 34 4习题 28.09 (dd, J = 8.5, 1.7 Hz, 1H) 7.58 (ddd, J = 8.6, 7.2, 1.7 Hz, 1H)7.14 (dd, J = 8.5, 1.4 Hz, 1H)6.97 (ddd, J = 8.4, 6.9, 1.4 Hz, 1H)4 = 7 + 1- 8 = 0H 的个数比为：1 : 6 : 9三个氧只能是烷氧基从偶合裂分规律及氢原子个数比知分子中有三个乙基 = C + 12H) (+2X2N5 = 8 +
