1、choose the correct meaning; (4) to correct the typos; (5) so the child write words (ABAB, and AABB); (6) in accordance with written words; (7) the complete word, and explain the meaning of the word; (8) collocation; (9) make sentences with the word; (10) the written language as required. (C) the mai
2、n sentence types (1) complete sentences; (2) write down the meaning of a sentence or expression of thoughts and feelings; (3) write sentences as required; (4) finish malalignment of the sentence; (5) modified sentences. 2, knowledge classification (1) the common conjunctions coordinate: . . 一面 . 1,
3、to examine the topic, identify problems associated with two 2, analysis, alternative question two is in direct proportion to the amount of the associated relationship is inversely proportional relationship. 3, and set unknown, column proportion type 4, and solutions proportion type 5, and test, wrot
4、e answer language plenary, and subject: application problem (1)-simple application problem and composite application problem review content simple application problem composite application problem answers application problem of general steps 1, and figure out meaning-through examines the, find known
5、 conditions and by seeking problem 2, and analysis number relationship-analysis known conditions Zhijian, and conditions and problem Zhijian of relationship, determine problem-solving method and problem-solving steps. 3, and column type calculation-lists formula, is out subdivisions 4, and test, and
6、 wrote answer-check, and checking, and wrote answers typical application problem 13, and subject: application problem (3)-column equation solutions application problem review content overview problem-solving steps 1, and figure out meaning, find by seeking of unknown and x said 2, and according to m
7、eaning find equivalent relationship, lists Equation 3, and solutions equation 4, and test, and wrote answers according to meaning find equivalent relationship of common method 1 , And according to common of number relationship type, established equivalent relationship 2, and according to has learn h
8、ad of calculation formula, 3, and according to problem in the of focus described sentence from overall Shang determine basic of equivalent relationship 4, and using segment figure, and list method, method analysis number美每家国际家居博览中心项目临时水电施工专项方案审核： 编制： 日期： 2011/8/1 中博建设集团有限公司重庆分公司美每家 国际家居博览中心工程项目部美每家研
9、发中心及标准厂房 F 号楼工程项目临时用水用电施工方案1目 录1、编制依据及说明 .22、工程概况 .23、现场用水、用电设计 .23.1、临时用水设计 .33.2、临时用电设计 .54、施工现场布置 .94.1、临时用水布置 .94.2、临时用电布置 .104.3、施工现场防雷措施 .115、施工现场用水用电安全技术措施 .116、消防措施 .13choose the correct meaning; (4) to correct the typos; (5) so the child write words (ABAB, and AABB); (6) in accordance with
10、written words; (7) the complete word, and explain the meaning of the word; (8) collocation; (9) make sentences with the word; (10) the written language as required. (C) the main sentence types (1) complete sentences; (2) write down the meaning of a sentence or expression of thoughts and feelings; (3
11、) write sentences as required; (4) finish malalignment of the sentence; (5) modified sentences. 2, knowledge classification (1) the common conjunctions coordinate: . . 一面 . 1, to examine the topic, identify problems associated with two 2, analysis, alternative question two is in direct proportion to
12、 the amount of the associated relationship is inversely proportional relationship. 3, and set unknown, column proportion type 4, and solutions proportion type 5, and test, wrote answer language plenary, and subject: application problem (1)-simple application problem and composite application problem
13、 review content simple application problem composite application problem answers application problem of general steps 1, and figure out meaning-through examines the, find known conditions and by seeking problem 2, and analysis number relationship-analysis known conditions Zhijian, and conditions and
14、 problem Zhijian of relationship, determine problem-solving method and problem-solving steps. 3, and column type calculation-lists formula, is out subdivisions 4, and test, and wrote answer-check, and checking, and wrote answers typical application problem 13, and subject: application problem (3)-co
15、lumn equation solutions application problem review content overview problem-solving steps 1, and figure out meaning, find by seeking of unknown and x said 2, and according to meaning find equivalent relationship, lists Equation 3, and solutions equation 4, and test, and wrote answers according to me
16、aning find equivalent relationship of common method 1 , And according to common of number relationship type, established equivalent relationship 2, and according to has learn had of calculation formula, 3, and according to problem in the of focus described sentence from overall Shang determine basic
17、 of equivalent relationship 4, and using segment figure, and list method, method analysis number21、编制依据及说明编制依据：根据美美每家研发中心及标准厂房 F 号楼工程施工现场用水、用电的需要，以及为了满足工期的要求，考虑到多个作业面的交叉作业的现场要求，根据建筑电气工程施工质量验收规范 （GB503032002） 、 施工现场临时用电安全技术规程 （JGJ46-2005）等规定，按照甲方提供的供电电源位置和供电功率，合理配置机械设备及电力设施。编制说明：本临时用水用电方案用于指导施工现场临建布置
18、，便于现场加强对现场用水用电进行安全技术管理提供理论依据。2、工程概况计 量单 位 方 案 批 准 数 据 本 次 报 批 数 据 备 注 16475.00 16475.00建 筑 占 地 面 积 9853.00 10054.90道 路 广 场 占 地 面 积 6013.00 6013.00绿 化 占 地 面 积 0.00 0.00 参 与 一 期 项 目 整 体 平 衡其 他 占 地 面 积 609.00 407.10 66947.80 67007.371 按 功 能 分研 发 中 心 46693.46 46875.76地 下 车 库 及 设 备 用 房 20254.34 20101.01配
19、 套 及 其 他 建 筑 面 积 0.00 30.602 按 地 上 地 下 分地 上 建 筑 面 积 46693.46 46906.36地 下 建 筑 面 积 20254.34 20101.01 不 计 入 容 积 率% 60.00 61.03 参 与 一 期 项 目 整 体 平 衡2.83 2.85 参 与 一 期 项 目 整 体 平 衡% 0.00 0.00 整 个 厂 区 综 合 绿 地 率 为 15.01%停 车 位 个 512 512 其 中 地 下 车 位 427， 地 面 车 位 85绿 地 率建 筑 工 程 综 合 技 术 经 济 指 标 一 览 表项 目建 设 用 地 总
20、面 积其 中总 建 筑 面 积其 中其 中 建 筑 密 度容 积 率美每家研发中心及标准厂房 F 号楼工程，工程占地面积 16475 平方米，规划总建筑面积为 67007.37M2。设计单位为机械工业第六设计研究院。3、现场用水、用电设计针对本工程的特点，为了确保现场施工的需要，合理组织生产提供良好的前提条件，根据现场实际情况和现行的施工用水用电管理规范，进行现场施工用水用电的设计。美每家研发中心及标准厂房 F 号楼工程项目临时用水用电施工方案33.1、临时用水设计临时用水包括施工用水q1 、施工机械用水q2 、施工现场生活用水 q3、生活区用水q4、消防用水q5。各用水量计算如下:1)施工现
21、场用水量按下式计算：q1=k1 360821KtTNQq1施工用水量k1用水系数取 1.15Q1工程量N1施工用水定额t1有效作业日T每天工作班数K2用水均衡系数取 1.5四个瓦工班 8 小时内的砌筑量 (每班以砌砖 20m3 计)混凝土养护 8 小时内用水 (自然养护以 20m3 计)N1 以每立方米砂浆搅拌耗水量取 600L/m3 计，每立方米混凝土养护耗水量以 300 L/m3 计。q1=1.15(33.2600+420200+300300)1.5/(83600)=6.69L/ S2 )施工机械用水量:q2=k1 36082KNQq2施工机械用水量choose the correct m
22、eaning; (4) to correct the typos; (5) so the child write words (ABAB, and AABB); (6) in accordance with written words; (7) the complete word, and explain the meaning of the word; (8) collocation; (9) make sentences with the word; (10) the written language as required. (C) the main sentence types (1)
23、 complete sentences; (2) write down the meaning of a sentence or expression of thoughts and feelings; (3) write sentences as required; (4) finish malalignment of the sentence; (5) modified sentences. 2, knowledge classification (1) the common conjunctions coordinate: . . 一面 . 1, to examine the topic
24、, identify problems associated with two 2, analysis, alternative question two is in direct proportion to the amount of the associated relationship is inversely proportional relationship. 3, and set unknown, column proportion type 4, and solutions proportion type 5, and test, wrote answer language pl
25、enary, and subject: application problem (1)-simple application problem and composite application problem review content simple application problem composite application problem answers application problem of general steps 1, and figure out meaning-through examines the, find known conditions and by s
26、eeking problem 2, and analysis number relationship-analysis known conditions Zhijian, and conditions and problem Zhijian of relationship, determine problem-solving method and problem-solving steps. 3, and column type calculation-lists formula, is out subdivisions 4, and test, and wrote answer-check,
27、 and checking, and wrote answers typical application problem 13, and subject: application problem (3)-column equation solutions application problem review content overview problem-solving steps 1, and figure out meaning, find by seeking of unknown and x said 2, and according to meaning find equivale
28、nt relationship, lists Equation 3, and solutions equation 4, and test, and wrote answers according to meaning find equivalent relationship of common method 1 , And according to common of number relationship type, established equivalent relationship 2, and according to has learn had of calculation fo
29、rmula, 3, and according to problem in the of focus described sentence from overall Shang determine basic of equivalent relationship 4, and using segment figure, and list method, method analysis number4k1用水系数取 1.15Q2同一种机械台数N2施工机械台班用水定额k3用水不均衡系数取 2.00根据现场施工机械计划初步估计,q 2=2.5 L/ S3)施工现场生活用水量q3= 608431tKN
30、pq3施工现场生活用水量P1施工现场高峰昼夜人数(人)，取 400 人N3施工现场生活用水定额( 一般为 2060L/人班), 取 40L/人班K4施工现场生活用水不均衡系数,取 1.5t每天工作班数q3=400*40*1.5/1*8*3600=0.83L/ S由于本工程的主要生活区不在现场,故用水量可以不计。4)生活区生活用水量根据现场实际情况,项目一期工程现场除安排办公室及部分临时生活设施外 ,主要生活区及工人生活区另设他处,故用水量不考虑。5)消防用水量 q5根据规定,现场面积在 5 公顷以内者同时发生火警 2 次, 消防用水定额按1015L/S 考虑,据现场占地面积, q5 暂按 15
31、L/S 考虑 .6)总用水量(Q)计算q1+q2+q3+q4q5,且工程面积小于 5 公顷美每家研发中心及标准厂房 F 号楼工程项目临时用水用电施工方案5故 Q= q5=15L/S7)供水管直径d= 104vQ管网中水流速度,取 =2.5vd= =0.087m105.24故选用供水管为100,现场总用水量约为 60t/h。甲方提供DN100 管径的给水管，满足需要。施工供水采用50的PVC管按照总平面布置图沿着基坑布置，每50m留置一个阀门。3.2、临时用电设计主要机械设备配置如下：序号 机械或设备名称 型号规格 数量额定功率（KW ）小计（KW ）1 塔吊 H3/36B 1 70 1402
32、钢筋切断机 GQ40-2 4 7.5 303 钢筋弯曲机 GJB40 4 3 124 钢筋调直机 4 3 125 电渣压力焊 HD-500 4 套 3 126 闪光对焊机 2 100 2007 插入振捣器 ZN60 10 1.1 118 交流焊机 BX3-300 4 24 969 手提电锯 MJ50 10 1.1 1110 圆盘锯 MJ105 4 4 1611 砂浆搅拌机 HJ-200 6 3 1812 施工井架 SS160 6 11 66choose the correct meaning; (4) to correct the typos; (5) so the child write w
33、ords (ABAB, and AABB); (6) in accordance with written words; (7) the complete word, and explain the meaning of the word; (8) collocation; (9) make sentences with the word; (10) the written language as required. (C) the main sentence types (1) complete sentences; (2) write down the meaning of a sente
34、nce or expression of thoughts and feelings; (3) write sentences as required; (4) finish malalignment of the sentence; (5) modified sentences. 2, knowledge classification (1) the common conjunctions coordinate: . . 一面 . 1, to examine the topic, identify problems associated with two 2, analysis, alter
35、native question two is in direct proportion to the amount of the associated relationship is inversely proportional relationship. 3, and set unknown, column proportion type 4, and solutions proportion type 5, and test, wrote answer language plenary, and subject: application problem (1)-simple applica
36、tion problem and composite application problem review content simple application problem composite application problem answers application problem of general steps 1, and figure out meaning-through examines the, find known conditions and by seeking problem 2, and analysis number relationship-analysi
37、s known conditions Zhijian, and conditions and problem Zhijian of relationship, determine problem-solving method and problem-solving steps. 3, and column type calculation-lists formula, is out subdivisions 4, and test, and wrote answer-check, and checking, and wrote answers typical application probl
38、em 13, and subject: application problem (3)-column equation solutions application problem review content overview problem-solving steps 1, and figure out meaning, find by seeking of unknown and x said 2, and according to meaning find equivalent relationship, lists Equation 3, and solutions equation
39、4, and test, and wrote answers according to meaning find equivalent relationship of common method 1 , And according to common of number relationship type, established equivalent relationship 2, and according to has learn had of calculation formula, 3, and according to problem in the of focus describ
40、ed sentence from overall Shang determine basic of equivalent relationship 4, and using segment figure, and list method, method analysis number613 套丝机 4 4 1614 潜水泵 8 3 2415 混凝土输送泵 HBT60 2 110 220合计 884根据机械表，本工程用电负荷可计算如下： P=1.05（k1P1/cos+k2p2+k3p3）其中：P 1 为电动机总功率p2 为电焊设备总容量p3 照明总功率k1=0.5，k 2=0.6，k 3=0.
41、8，cos=0.7最大用电量出现在主体施工阶段后期，砌体插入阶段。P1= k1P1/cos=0.5（140+30+12+12+11+16+18+66+16+220） /0.7=386kwP2= k2p2=0.5（12+200+96 ）=154kw由于生活区不在设置在现场，照明总功率按现场机械用电量 10%（约55kw）进行考虑， P3=0.860=28kwP=1.05（386+154+28）=568kw本工程由业主提供 1250KW 变压器,由于各种设备的运行情况不同，各种设备不在同一时间段内使用，综合考虑现场的使用情况，业主提供的 1250KVA变压器能满足施工需要。3.2.1、用电回路的布
42、置美每家研发中心及标准厂房 F 号楼工程项目临时用水用电施工方案7本工程临时用电是从业主方提供的 1250KVA 引出的 380V 电源，现场设置一级配电箱 1 个，二级配电箱 3 个（1# 塔吊、1#钢筋加工房、1#木工房、1#电动混凝土输送泵、1#塔吊覆盖施工范围内用电一个回路；2# 塔吊、2#钢筋加工房、2#木工加工场、2#电动混凝土输送泵、2#塔吊覆盖施工范围一个回路；3#主管现场办公区域） ，现场根据机械的使用情况配置适当的移动配电箱，具体位置详总平面布置图。总配电箱内配置：漏电保护断路器（DZ10LE400/430） 4 个刀开关（HD13BX1000/31） 1 个分配电箱内配置
43、：漏电保护断路器（DZ15LE100/490） 4 个漏电保护断路器（DZ15LE63/290） 1 个断路器（DZ10250/330 ） 1 个移动配电箱：漏电保护断路器（DE15LE63/490） 1 个漏电保护断路器（DE15LE40/490 ） 3 个漏电保护断路器（DE18LE20A ） 3 个断路器（DZ10100/330 ） 1 个断路器（DZ1063/330） 1 个插座（四孔 16A、三孔 16A） 各 3 个（1）第一个回路用电负荷统计P1=270KW（2）第二个回路用电负荷统计P2=270KWchoose the correct meaning; (4) to corre
44、ct the typos; (5) so the child write words (ABAB, and AABB); (6) in accordance with written words; (7) the complete word, and explain the meaning of the word; (8) collocation; (9) make sentences with the word; (10) the written language as required. (C) the main sentence types (1) complete sentences;
45、 (2) write down the meaning of a sentence or expression of thoughts and feelings; (3) write sentences as required; (4) finish malalignment of the sentence; (5) modified sentences. 2, knowledge classification (1) the common conjunctions coordinate: . . 一面 . 1, to examine the topic, identify problems associated with two 2, analysis, alternative question two is in direct pro
