6.8 设有如下一组推理规则设有如下一组推理规则:r1:IF E1 THEN E2(0.6)r2:IF E2 AND E3 THEN E4(0.7)r3:IF E4 THEN H(0.8)r4:IF E5 THEN H(0.9)且已知且已知CF(E1)=0.5,CF(E3)=0.6,CF(E5)=0.7。求求CF(H)=?解解：(1)先由先由r1求求CF(E2)CF(E2)=0.6 max0,CF(E1)=0.6 max0,0.5=0.3(2)再由再由r2求求CF(E4)CF(E4)=0.7 max0,minCF(E2),CF(E3)=0.7 max0,min0.3,0.6=0.21(3)再由再由r3求求CF1(H)CF1(H)=0.8 max0,CF(E4)=0.8 max0,0.21)=0.168(4)再由再由r4求求CF2(H)CF2(H)=0.9 max0,CF(E5)=0.9 max0,0.7)=0.63(5)最后对最后对CF1(H)和和CF2(H)进行合成，求出进行合成，求出CF(H)CF(H)=CF1(H)+CF2(H)+CF1(H)CF2(H)=0.6924.9 设有一
