1、网路诊断与分析实训岗位：网管( 7 )实训人员(1 行 1 名字)请尽量独立自主完成，认真学习参考资料 Part1 文档和命令帮助（命令 /? ）为提高效率，建议开启多个命令窗口进行各项测试。完成后及时上交以便评审(请勿修改文件名)。课后由老师统一讲评。注意：命令记录要求记录的是文本内容(不是截图！)文本复制方法如下图所示：提示：可以多开几个命令视窗同时进行多个测试，提高效率！Ping 网路分析（1） 分别 ping 和 命令记录网管7 C:ping http:/Pinging 61.139.2.69 with 32 bytes of data:Request timed out.Repl
2、y from 61.139.2.69: bytes=32 time=6ms TTL=56Reply from 61.139.2.69: bytes=32 time=6ms TTL=56Request timed out.Ping statistics for 61.139.2.69:Packets: Sent = 4, Received = 2, Lost = 2 (50% loss),Approximate round trip times in milli-seconds:Minimum = 6ms, Maximum = 6ms, Average = 3ms网管7 C:ping Pingi
3、ng 202.98.160.68 with 32 bytes of data:Request timed out.Request timed out.Request timed out.Reply from 202.98.160.68: bytes=32 time=26ms TTL=244Ping statistics for 202.98.160.68:Packets: Sent = 4, Received = 1, Lost = 3 (75% loss),Approximate round trip times in milli-seconds:Minimum = 26ms, Maxim
4、um = 26ms, Average = 6ms分析 计算各自的网络距离，分析到哪个目标更近？结论 计算过程及结论：到达目标更近（2） 如何用 ping 获知 202.196.64.1的主机名 ？命令记录网管7 C:ping -a 202.196.64.1Pinging 202.196.64.1 with 32 bytes of data:Request timed out.Request timed out.Request timed out.Request timed out.Ping statistics for 202.196.64.1:Packets: Sent = 4, Rece
5、ived = 0, Lost = 4 (100% loss),Approximate round trip times in milli-seconds:Minimum = 0ms, Maximum = 0ms, Average = 0ms结论 为本主机名（3）测试：ping 202.97.50.162 的 最大字节？（注意：只记录 最终的两次 （正负1个字节！）命令记录网管7 C:ping -l 1469 202.97.50.162Pinging 202.97.50.162 with 1469 bytes of data:Request timed out.Request timed out
6、.Request timed out.Request timed out.Ping statistics for 202.97.50.162:Packets: Sent = 4, Received = 0, Lost = 4 (100% loss),Approximate round trip times in milli-seconds:Minimum = 0ms, Maximum = 0ms, Average = 0ms网管7 C:ping -l 1468 202.97.50.162Pinging 202.97.50.162 with 1468 bytes of data:Reply fr
7、om 202.97.50.162: bytes=1468 time=52ms TTL=245Reply from 202.97.50.162: bytes=1468 time=58ms TTL=245Reply from 202.97.50.162: bytes=1468 time=52ms TTL=245Reply from 202.97.50.162: bytes=1468 time=49ms TTL=245Ping statistics for 202.97.50.162:Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),Approx
8、imate round trip times in milli-seconds:Minimum = 49ms, Maximum = 58ms, Average = 52ms结论 最大字节为1468（4） ping 202.202.216.5命令记录网管7 C:ping Pinging 202.202.216.5 with 32 bytes of data:Request timed out.Request timed out.Request timed out.Request timed out.Ping statistics for 202.202.216.5:Packets: Sent =
9、 4, Received = 0, Lost = 4 (100% loss),Approximate round trip times in milli-seconds:Minimum = 0ms, Maximum = 0ms, Average = 0ms分析 返回的ICMP差错报文表示什么问题？结论 回答：超时路由分析 （1） tracert 分析路由过程命令记录网管7 C:tracert Tracing route to 221.236.12.130over a maximum of 30 hops:1 1 ms tracert 218.6.187.1Tracing route to
10、218.6.187.1 over a maximum of 30 hops1 1 ms 1 ms tracert 202.202.216.5Tracing route to 202.202.216.5 over a maximum of 30 hops1 pathping -q 255 202.97.50.162Tracing route to 202.97.50.162 over a maximum of 30 hops0 nms07 192.168.4.341 192.168.4.32 192.168.4.23 10.1.1.14 10.10.7.65 10.2.9.96 10.2.9.9
11、7 182.151.230.628 182.151.191.419 221.237.185.4110 222.213.14.16511 202.97.37.11312 202.97.36.7713 202.97.50.162Computing statistics for 828 seconds.(2)Pathping 202.97.50.162 分析该路由通路的拥塞情况。(注意:时间需要几分钟！请保持切勿中断！每隔1分钟敲回车几下，以便数据显出。某些节点可能不回应ICMP(显示* lost 100%)，请忽略这些节点)命令记录 网管7 C:pathping Tracing route to
12、202.97.50.162 over a maximum of 30 hops0 nms07 192.168.4.341 192.168.4.32 192.168.4.23 10.1.1.14 10.10.7.65 10.2.9.96 10.2.9.97 182.151.230.628 182.151.191.419 221.237.185.4110 222.213.14.16511 202.97.37.11312 202.97.36.7713 202.97.50.162Computing statistics for 325 seconds.Source to Here This Node/
13、LinkHop RTT Lost/Sent = Pct Lost/Sent = Pct Address0 nms07 192.168.4.340/ 100 = 0% |1 0ms 0/ 100 = 0% 0/ 100 = 0% 192.168.4.30/ 100 = 0% |2 0ms 0/ 100 = 0% 0/ 100 = 0% 192.168.4.20/ 100 = 0% |3 6ms 7/ 100 = 7% 7/ 100 = 7% 10.1.1.10/ 100 = 0% |4 - 100/ 100 =100% 100/ 100 =100% 10.10.7.60/ 100 = 0% |5
14、 - 100/ 100 =100% 100/ 100 =100% 10.2.9.90/ 100 = 0% |6 - 100/ 100 =100% 100/ 100 =100% 10.2.9.90/ 100 = 0% |7 5ms 6/ 100 = 6% 6/ 100 = 6% 182.151.230.620/ 100 = 0% |8 7ms 13/ 100 = 13% 13/ 100 = 13% 182.151.191.410/ 100 = 0% |9 6ms 7/ 100 = 7% 7/ 100 = 7% 221.237.185.410/ 100 = 0% |10 5ms 4/ 100 =
15、4% 4/ 100 = 4% 222.213.14.1650/ 100 = 0% |11 10ms 32/ 100 = 32% 32/ 100 = 32% 202.97.37.1130/ 100 = 0% |12 40ms 10/ 100 = 10% 10/ 100 = 10% 202.97.36.770/ 100 = 0% |13 47ms 0/ 100 = 0% 0/ 100 = 0% 202.97.50.162Trace complete.分析 路由通路中是否有明显的阻塞(30%)或拥塞(10%)发生？如果有的话，阻塞或拥塞主要发生在哪些设备及方向(收 或 发)？结论 设备3就发 4、5、6收发设备完全阻塞 ； 10设备发 11设备收
