1 RT2级通用试卷 090219 改.doc

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1、精品文档就在这里-各类专业好文档,值得你下载,教育,管理,论文,制度,方案手册,应有尽有-YXHW GENERAL EXAMINATION PAPER FOR ASME RT LEVEL ASME RT - 级通用试卷 Approved by 试题批准人:EXAMINEE应试人EXAMINER考评人Grade得 分DATE日 期DATE日 期Choose the correct answer:选出正确的答案:. Physics ( No.1-10; 10 Questions; 2.5 % each, total 25% ) 物理基础 (No.1-10题;10题;每题2.5分, 共25分 )1.

2、 Charged particles passing through matter lose energy primarily because of ( ) A. Scatter radiation. B. Secondary Scatter.C. Ionization. D. Charged electrons.带电粒子通过物质时会损失能量,主要是由什么引起? ( )A散射线。 B. 二次散射线。C. 电离。 D. 带电电子。2 The penetrating power of an X-ray beam is a function of its: ( ) A. angle of incid

3、ence. B. source-to-object distance.C. wavelength. D. tube current.X射线束的穿透力随下列哪一因素而变化? ( ) A. 入射角。 B. 射源到工件表面距离。 C. 射线波长。 D. 管电流。3 What radioisotope has a gammar ray energy emission that is approximately equal to 320 kV radiation from an X-ray tube? ( )A. Co-60. B. Cs-137.C. Ur-238. D. Ir-192.下列哪种放射性

4、同位素辐射的射线能量中,有大致相当于X射线管产生的320kV射线? ( )A. Co-60。 B. Cs-137。C. Ur-238。 D. Ir-192。4 Attenuation of X-rays in the energy range commonly used for testing takes place through ( ) A. photoelectric absorption. B. Compton absorption. C. both A and B D. neither A and B在常用能量范围内,X射线通过什么过程发生衰减? ( )A. 光电吸收 B. 康普顿吸

5、收C. A和B D. A和B都不是5 You have an Ir-192 source whose strength was 3.7 TBq (100Ci) on July 1 this year. Approximately what will be its strength on September 13 this year if the half life of Ir-192 is 75 days? ( ) A. 1TBq (30Ci). B. 0.93 TBq (25Ci).C. 2.6 TBq (70Ci). D. 1.9 TBq (50Ci).已知今年7月1日,你手头的Ir-19

6、2源源强为 3.7 TBq (100Ci),问到今年11月27日,其源强约为多少?(已知Ir-192的半衰期为75天) ( )A. 1TBq (30Ci). B. 1.9 TBq (50Ci).C. 2.6 TBq (70Ci). D. 3.3 TBq (90Ci).6 Radiation scattering increases as ( )A. the energy of the incident radiation decreases.B. the sign of the radiation field increases.C. the angle of scatter decrease

7、s.D. all of the above. 在什么情况下,散射线强度会增大? ( ) A. 入射线能量降低时 B. 照射场尺寸增大时 C. 散射角减小时 D. 以上都是7 The half-value layer of lead for cobalt-60 is approximately 0.5 inch (13mm). If the radiation level on the source side of a 1.54 inch (39mm) lead plate is 80R/hr, the radiation level on the opposite side is: ( ) A

8、. 8R/hr; B. 10R/hr; C. 20R/hr; D. 40R/hr.Co-60 的铅半值层约13mm,若在39mm厚的铅板射源侧表面辐射强度为80R/hr,则铅板背面的辐射强度为: ( )A. 8R/hr。 B. 10R/hr。 C. 20R/hr。 D. 40R/hr。8 By the 200KV X-rays we mean ( )A. the homogeneous rays of energy 2 MeV.B. the all compositions of the rays of energy higher than 0.2 MeV.C. the “white X-ra

9、ys” beam of the highest energy 0.2 MeV.D. The X-rays of the average energy 0.2 MeV.通常所谓200KVX射线是指: ( )A. 能量为0.2 MeV的单能射线。B. 能量高于0.2 MeV的所有射线成分。C. 最大能量为0.2 MeV的“白色”X射线束。D. 平均能量为0.2 MeV的X射线束。9 In comparison with lower-voltage radiographs, high energy radiographs show ( )A. great contrast B. great lati

10、tudeC. great amounts of scatter radiation relative to primary beam intensity.D.none of the above.用高能射线拍出的射线底片,比低电压射线拍出的底片: ( )A. 对比度高 B. 宽容度大C. 散射比大 D. 以上都不是10Filters used at the port of the X-ray tube: ( )A. intensify the X-ray beam by contributing secondary radiation.B. filter short wavelength X-r

11、ay beams to provide “softer” radiation.C. provide the most readily adjusted means of modifying X-ray intensity.D. filter out “soft” radiation to provide a more homogeneous X-ray beam.X射线管窗口放置滤板的目的是: ( )A. 产生二次射线以增强X射线束。B. 滤去波长短的X射线以获得“软”射线。C. 使X射线强度易于调整。D. 滤去“软”射线,以获得较均匀的X射线束。. Equipment (No.11-15;

12、5 Questions;2 % each,total 10% ) 设备(No.11-15; 5题,每题2分,共10分)11The maximum tube current of an X-ray tube is determined by the: ( )A. composition of the cathode. B. distance from the anode to the cathode.C. target material, size of the focal spot, and efficiency of the cooling system. D. material used

13、to construct the vacuum envelope.X射线管最大管电流取决于: ( )A. 阴极结构。 B. 阳极到阴极的距离。C. 靶材、焦点尺寸以及冷却系统的效率。 D. 制作真空管所用材料。12 The inherent filtration of an X-ray tube is a function of ( ) A. he thickness and composition of the X-ray tube port.B. the voltage setting of the instrument.C. the source-to-object distance.D

14、. the material used as a target. X射线管的固有滤波值取决于: ( )A. X射线管窗口厚度和成份。 B. 仪器的电压调节器。C. 射线源工件距离。 D. 靶材。13. The focal spot in an X-ray tube: ( )A. is inclined at an angle of 30from the normal to the tube axis.B. is maintained at a high negative voltage during operations.C. should be as large as possible to

15、 ensure a narrow beam of primary radiation.D. should be as small as possible without unduly shortening the life of the tube.X射线管的焦点: ( )A. 与管轴法线成30倾角。 B. 工作时带负高压。C. 应尽量大,以保证主射线成窄束。 D. 在不影响管子寿命的前提下应尽量小。14. Which of the following factors must be considered when choosing the type of film? ( ) A. The co

16、mposition, size, and thickness of the object.B. Energy and output of the radiation source.C. The criticality of the inspection, and the required level of sensitivity.D. All of the above.选定胶片类型时,射线照相人员必须考虑下列哪一因素? ( ) A. 工件材质、尺寸和厚度。 B. 射线源能量和输出。 C. 检验的危险程度,以及所要求的灵敏度水平。 D. 以上都得考虑。15. A high-vacuum envi

17、ronment for X-ray tube elements is necessary for which of the following? ( )A. To prevent oxidation of the electrode materials.B. To prevent ready passage of the electron beam without ionization of gas within the tube.C. To provide electrical insulation between the electrodes.D. All of the above.X射线

18、管需要高真空的原因是: ( )A. 防止电极材料氧化。B. 使管内气体不被电离,从而使电子束易于通过。C. 使电极之间绝缘。D. 以上都是。. Radiographic Technique ( No.16-30; 15 Questions;3% each,total 45%)透照工艺 ( No.16-30; 15题;每题3分,共45分 )16. All other factors being the same, radiographic sharpness or definition is improved by using: ( )A. slower film. B. faster film

19、.C. film with a larger grain size.D. slower film with fluorescent screens.其它条件相同,要提高射线照相清晰度或分辨率,可使用: ( )A速度较慢的胶片。 B. 速度较快的胶片。C. 颗粒较大的胶片。 D .慢速胶片+荧光增感屏。17. A source-to-film distance of 750 mm is changed to 600 mm. What exposure time would be required if the original exposure time was 10 min? ( )A. 2.

20、5 min. B. 5.0 min.C. 6.4 min. D. 15.2mm.原曝光时间为10min,射线源-胶片距离为750mm,底片可得正常黑度,现射源-胶片距离改为600mm,为得相同黑度,问所需曝光时间为多少? ( ) A. 2.5 min. B. 5.0 min.C. 6.4 min. D. 15.2mm. 18. As the effective energy of the radiation increases up to about 250KV. ( )A. film graininess increasesB. film graininess decreasesC. rad

21、iographic definition increasesD. film speed keeps constant射线有效能量增大到约250KV时, ( )A. 胶片颗粒性减小。 B. 胶片颗粒性增大。C. 照相清晰度提高。 D. 胶片速度不变。19. Increasing the X-ray or gamma-ray energy will ( )A. significantly decrease the average gradient of D-lgE curve.B. significantly increase the average gradient of D-lgE curve

22、.C. increase the slope of a characteristic curve.D. have little effect on the shape of a characteristic curve.X射线或r射线能量提高时: ( )A. 胶片特性曲线平均梯度显著增大。B. 胶片特性曲线平均梯度显著增小。C. 胶片特性曲线斜率增大。D. 对特性曲线形状几乎无影响。20. In order to utilize the principles of geometric enlargement ( placing film at a distance from the speci

23、men ). ( )A. the source-to-specimen distance must be one-half the source-to film distance.B. the source of radiation must be extremely small.C. a magnetic focusing coil must be used near the port of the X-ray tube.D. the specimen must be of uniform thickness.为利用几何放大原理(即胶片与试件底面相隔一定距离): ( ) A射线源试件距离应为

24、射源胶片距离之半。 B射线源必须很小。 CX射线管窗口须放置磁聚焦线圈。 D试件厚度必须均匀。21. As the development time increases ( )A. the characteristic curve grows steeper and moves to the left.B. the characteristic curve grows steeper and moves to the right.C. the characteristic remains the same in shape but moves to the left.D. There is l

25、ittle effect on the characteristic curve.显影时间延长时: ( ) A. 特性曲线变陡并左移。 B. 特性曲线变陡并右移。 C. 特性曲线不变,位置左移。 D. 对特性曲线几乎无影响。22In order to increase latitude so that thick and thin portions may be radiographed at reasonable viewing densities simultaneously ( )A. a fluorescent screen should be employed.B. the film

26、 cassette may be loaded with two separate film with one film placed on top of the order.C. the film cassette may be loaded with two films of different speeds.D. None of the above are practical means of increasing latitude.为增大宽容度,使厚薄两部分同时透照后获得适于观察的黑度: ( ) A. 应使用荧光增感屏。 B. 在胶片暗袋中装两张同速胶片。 C. 在胶片暗袋中装两张异速

27、胶片。 D. 以上方法对增大宽容度均不可行。23. Developer solution should be discarded when the quantity of replenisher added equals ( )A. the original quantity of developer.B. two to tree times the original quantity of developer.C. five to six times the original quantity of developer.D. ten times the original quantity o

28、f developer.当补充添加量达到多少时显影液应废弃? ( )A. 原显影液量。 B. 23倍原显影液量。C. 56倍原显影液量。 D. 10倍原显影液量。24. The loading bench in a dark room should be: ( ) A. next to the film processing tanks or machine.B. away from the film processing tanks or machine. C. near the entrance for convenience in passing films in and out of

29、darkroom.D. near the vent fan to ensure a good rate of air flow over the film as it is loaded in the cassettes or film holders. 暗室装片工作台应 ( )A. 紧靠洗片箱或自动洗片机。 B. 远离洗片箱或自动洗片机。C. 靠近暗室入口,以使胶片出入暗室方便。D. 靠近通风机,以保证暗袋装片时通风良好。25. Washing film in cold water (less than 10) during manual film processing results in

30、: ( ) A. uniform drawing of water from the film. B. improved results from the film drying process.C. Greater washing action.D. Little washing action taking place. 手工洗片过程中,在低于 10的冷水中冲洗胶片会 ( )A. 使胶片脱水均匀。 B. 使胶片干燥过程效果良好。C. 增强水洗作用。 D. 弱化甚至阻碍水洗作用。26. Static marks in radiographs may results of ( )A. using

31、 contaminated cotton gloves. B.using non interleaved film.C. sliding film rapidly out of the film holder. D. loading several films into one film holder. 射线底片上的静电斑点或静电斑汶可能是由下列哪种原因引起的? ( ) A. 因取片时手上戴了受污染的棉手套。 B. 因使用了无衬纸的胶片。C. 因从胶片暗袋中抽取胶片时动作快猛。 D. 因一个胶片暗袋中装了几张胶片。27. The purpose of agitating an X-ray fi

32、lm during development is to ( ) A. protect the film from excessive pressure.B. renew the development at the surface of the film.C. disperse unexposed silver grains on the film surface.D. prevent reticulation.显影过程中晃动X射线胶片的目的是: ( )A. 保护胶片免受过压。 B. 使胶片表面的显影液更新。C. 使胶片表面未曝光眼粒子散开。 D. 防止起皱。28. Processing ta

33、nks should be periodically cleaned and sterilized. Which of the following agents in solution is recommended? ( ) A. Sodium hypochlorite B. Acetone C. Household detergent D. Hydrochloric acid 洗片箱应定期清洗和消毒,推荐用于清洗、消毒的化学药剂是: ( )A. 次氯酸钠 B. 丙酮C. 家用去污剂 D. 盐酸29. Using the formula given EPS=100/x(TH/2)0.5 , calculate the equivalent sensitivity of an ASME#20 penetrameter showing the 2T hole on a 1.25in thick specimen. ( )A. 2.0% B. 1.6%C. 1.8% D. 1.4%透照厚1.25英寸钢试件,底片上显示出ASME#20透度计的2T孔,则其等效透度计灵敏度EPS*为* 等效透度计灵敏度计算式:EPS=100/x(TH/2)0.5 (

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