2.21 某办公楼工程地质勘探中取原状土做试验。用天平称50cm3湿土质量为95.15g，烘干后质量为75.05g，土粒比重为2.67。计算此土样的天然密度、干密度、饱和密度、天然含水率、孔隙比、孔隙率以及饱和度。【解】m = 95.15g，ms = 75.05g，mw = 95.15 - 75.05 = 20.1g，V = 50.0 cm3，ds = 2.67。V s = 75.05/(2.671.0) = 28.1 cm3取g = 10 m/s2，则V w = 20.1 cm3V v = 50.0 - 28.1 = 21.9 cm3V a = 50.0 28.1 20.1 = 1.8 cm3于是，r = m / V = 95.15 / 50 = 1.903g/ cm3rd = ms / V = 75.05 / 50 = 1.501g/ cm3rsat = (ms + rw V v)/ V = (75.05 + 1.0 21.9) / 50 = 1.939g/ cm3w = mw / ms = 20.1 / 75.05 = 0
