数值分析作业(C语言编程实现)(共12页).doc

#include #include double f(double x)double ans; ans=exp(x); return ans;void main()double a=1,b=3,error=0.0001,t2020,h,c;int i,j,k,m,n;h=b-a;t00=h*(f(a)+f(b)/2;k=1;while(1)t0k=0;m=1;for(j=0;jk-1;j+)m=m*2;for(i=1;i=m;i+)t0k=t0k+h*f(a+(i-0.5)*h);t0k=(t0k+t0k-1)/2;for(j=1;j=k;j+)c=1;for(n=0;nj;n+)c=c*4;tjk-j=(c*tj-1k-j