计算行简化阶梯形矩阵(共1页).doc

精选优质文档-倾情为你奉上#include#define N 4int main()void print(float arN);float aNN,fir,t; int i,j,x,k; for(i=0;iN;i+) for(j=0;jN;j+) scanf(%f,&aij); printf(Its the matrix that you have input:n); print(a); for(x=0;xN;x+) for(i=x;iN;i+) fir=aix; if(fir=0) continue; for(j=x;jN;j+) aij=aij/fir; for(i=x;iN;i+) if(aix=1) for(j=x;jN;j+) t=aij;aij=axj;axj=t; break; for(